If the frequencies of alleles A and B are 0.2 and 0.6, respectively, what is the probability of an AA child in a mating of AB x AB parents?

To determine the probability of having an AA child from a mating of AB x AB parents, we can use a Punnett square to visualize the potential genetic combinations. Each parent contributes one of their alleles to the offspring.

In this scenario, each AB parent can pass on either the A allele or the B allele, leading to the following possible combinations for the offspring:

1. AA (A from the first parent and A from the second parent)
2. AB (A from the first parent and B from the second parent)
3. BA (B from the first parent and A from the second parent)
4. BB (B from both parents)

We can summarize these outcomes based on the allele frequencies:

• The probability of an offspring being AA is the product of the probabilities of each parent contributing an A allele. Each AB parent has a 0.2 (or 20%) chance of passing on an A allele. Thus, the probability for AA offspring is calculated as:

[ P(AA) = P(A \text{ from parent 1}) \times P(A \text{ from parent 2}) = 0.2 \times 0.2 = 0.04 ]

However, in this case,